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CAMBRIDGE O LEVEL · 2025–2027

Indices II.

Extend index rules to algebraic expressions and solve equations using a common base.

Syllabus 2.4Visual notesWorked examples
BY THE END

Use all types of indices · simplify algebraic powers · solve common-base equations

01

Keep the base; operate on the indices

The index rules you used for numbers apply to letters because the repeated-factor idea is unchanged. Three factors of x multiplied by two more factors of x give five factors of x.

Keep coefficients and letter powers separate at first. In 2x³ × 4x², the coefficients multiply to 8 while the five factors of x give x⁵. Restrictions still matter: a negative power of x requires x not to be zero.

The laws from Number still apply when indices contain letters. For fractional indices in these examples, take the base to be positive; division and negative powers require a non-zero base.

Index rules
Multiplyxaxb = xa+b
Dividexaxb = xa−b
Power of a power(xa)b = xab
Zero and negativex⁰ = 1; x−a = 1xa
Fractionalx12 = √x; x23 = (∛x)²
WORKED EXAMPLE

Simplify 3x² × 4x⁻12.

12x2−12 = 12x32

Multiply coefficients separately from the powers.

WORKED EXAMPLE

Simplify 5x1/2x⁻².

5x12−(−2) = 5x52
Pause and explainWhy does x³ × x² give x⁵ rather than x⁶?

There are 3 + 2 factors of x altogether. Multiplying indices is the rule for a power raised to another power, not this product.

02

Use a common base to solve equations

An equation with powers can sometimes be solved by expressing both sides with the same base. Once the base is a positive number other than 1, matching powers requires matching exponents.

For example, 8 can be rewritten as 2³, so 2ˣ = 8 becomes 2ˣ = 2³ and x = 3. First rewrite both sides, then simplify their exponents using index rules. Do not equate exponents while the bases are still different.

WORKED EXAMPLE

Solve 32x = 27.

Write 27 as 3³. Equal powers of the same positive base (other than 1) have equal indices.

2x = 3, so x = 32
WORKED EXAMPLE

Solve 5x+1 = 25x.

5x+1 = 52x
x + 1 = 2x, so x = 1
WORKED EXAMPLE

Solve 8x = 4.

23x = 2², so 3x = 2 and x = 23
Pause and explainWhat first step helps solve 3ˣ = 27?

Write 27 as 3³. Both sides then have base 3, making x = 3 clear.

03

Your turn. State your base.

Expand a short repeated product if you are unsure which index rule applies. Check whether the operation is multiplication, division or raising a power.

For exponential equations, show the common base explicitly before comparing the exponents. Substitute your final value into the original equation to confirm that both numerical sides agree.

1

Simplify (2x³)² × x⁻⁴.

Reveal worked answer
4x⁶ × x⁻⁴ = 4x², with x ≠ 0 in the original expression.
2

Simplify (x53)32 for x > 0.

Reveal worked answer
Multiply the indices to obtain x52.
3

Solve 9x−1 = 27.

Reveal worked answer
32x−2 = 3³, so 2x − 2 = 3 and x = 52.