Surface area and volume.
Separate the space a solid holds from the faces and curved surfaces that cover it.
Calculate with cuboids, uniform prisms, cylinders, spheres, pyramids and cones · distinguish curved and total areas
Surface area covers faces; volume fills space
Surface area measures the material covering a solid, while volume measures the space it occupies. Think of wrapping a gift compared with filling a container: these require different calculations.
Before choosing a formula, identify the solid and the meaning of each labelled dimension. A radius, a vertical height and a slant height are not interchangeable. The diagrams below show which measurements belong to each formula, so refer to the shape rather than memorising symbols alone.
Surface area uses square units; volume uses cubic units. Identify the surfaces included in the question and the perpendicular height before choosing a formula.
| Solid | Volume | Surface area |
|---|---|---|
| Cuboid | lwh | 2(lw + lh + wh) |
| Right prism | Cross-sectional area A × length L | 2A + PL, where P is cross-section perimeter |
| Cylinder | πr²h | Curved: 2πrh Total: 2πrh + 2πr² |
| Sphere | 43 πr³ | 4πr² |
| Pyramid | 13 × base area × perpendicular height | Base area + areas of triangular faces |
| Right circular cone | 13πr²h | Curved: πrℓ Total: πrℓ + πr² |
Pause and explainWould paint needed for a solid depend on its volume or its exposed surface area?
Its exposed surface area. Paint covers surfaces rather than filling the interior.
Cuboids and uniform cross-sections
A prism has a cross-section that stays the same along its length. Imagine stacking identical thin slices: the area of one slice multiplied by the stacking length gives the volume.
Find the cross-sectional area first, even when that cross-section is a triangle or a compound shape. For surface area, count the end faces and the side faces separately. A cuboid is a familiar prism whose rectangular faces make those pieces easy to list.
A cuboid measures 8 cm by 5 cm by 3 cm. Find volume and surface area.
SA = 2(8 × 5 + 8 × 3 + 5 × 3) = 158 cm²
A triangular prism has a 3–4–5 right-triangle cross-section and length 10 cm.
Cross-section area A = 12 × 3 × 4 = 6 cm². Cross-section perimeter P = 12 cm.
SA = 2 × 6 + 12 × 10 = 132 cm²
A uniform semicircular prism has radius 3 cm and length 10 cm.
Cross-section area = 9π2 cm². Cross-section perimeter includes its diameter: 3π + 6 cm.
SA = 9π + (3π + 6) × 10 = 39π + 60 cm²
A uniform sector cross-section also uses V = cross-sectional area × length. It need not be a polygonal cross-section for these mensuration questions.
Pause and explainWhy is cross-sectional area multiplied by prism length rather than by a sloping edge of the cross-section?
The length measures how far the unchanged cross-section extends through the solid. A different edge does not measure the stacking direction.
Cylinders: count the circular ends
A cylinder is a prism with circular ends. If its curved surface is unrolled, it becomes a rectangle whose width is the circumference and whose height is the cylinder’s height.
This explains the curved-area formula. Total surface area adds the circular ends that are actually present. Read whether the container is closed, open at the top, or open at both ends before counting circles; the same curved surface can accompany different total areas.
Curved wall = 2π × 3 × 8 = 48π cm².
Two ends = 18π cm².
Volume = 72π cm³
Assume negligible wall thickness. Removing a lid changes surface area, but not the space enclosed up to the rim.
An open cylindrical tank has radius 2 m and height 5 m. Find material area and capacity.
With no lid, include the curved wall and one bottom circle.
Capacity = π(2²)(5) = 20π m³ = 20 000π litres
Pause and explainHow many circular ends are included for a cylinder open only at the top?
One, the base. The missing top circle is not part of the material surface.
Cones and pyramids: distinguish the heights
Cones and pyramids taper to a point, so their volume is smaller than a prism with the same base and perpendicular height. Their volume is one third of that matching prism’s volume.
Distinguish the perpendicular height used for volume from a slant height used for a cone’s curved area or a pyramid face’s area. A right-angled triangle inside the solid may connect them. Label the relevant triangle before using Pythagoras to find a missing dimension.
A right cone has radius 3 cm and perpendicular height 4 cm. Find its volume and total surface area.
Slant height ℓ = √(3² + 4²) = 5 cm.
SA = π × 3 × 5 + π × 3² = 24π cm²
A right square-based pyramid has base side 6 cm, perpendicular height 4 cm and each triangular-face slant height 5 cm.
SA = 6² + 4(12 × 6 × 5) = 96 cm²
The perpendicular height goes from apex to base plane. The face slant height goes from apex to the midpoint of a base edge.
Pause and explainWhich height is used in a cone’s volume formula?
The perpendicular height from its vertex to the plane of its circular base, not the sloping side length.
Spheres and hemispheres
A sphere is the surface shape of a ball; its radius measures from its centre to the surface. A hemisphere is half of that solid, but cutting it in half creates a new circular face.
Therefore a hemisphere’s volume is half the sphere’s volume, while its total surface area is not merely half the sphere’s surface area. Add the flat circular base when it is exposed. Always separate curved area from total area in your description.
Find volume and surface area of a sphere with radius 6 cm.
SA = 4π × 6² = 144π cm²
A hemisphere has half the sphere’s volume and half its curved surface area. A closed hemisphere also has one flat circular base.
Curved area = 2πr²
Total closed surface area = 3πr²
A solid hemisphere has radius 4 cm. Find its total surface area.
Using 32π cm² would count only the curved part.
Pause and explainWhy does a closed hemisphere need an extra circle in its surface-area calculation?
Cutting the sphere creates a flat circular base. That face belongs to the hemisphere’s total exterior surface.
Your turn. Name the surfaces you include.
Sketch or name each surface before adding areas. For volume, identify the solid’s base area and perpendicular height or radius as required.
Check whether the question asks for curved area, total area, capacity or volume. State square or cubic units, and retain exact π expressions when the answer requires them.
A closed cylinder has radius 4 cm and height 7 cm. Find volume and total surface area.
Reveal worked answer
A right cone has radius 5 cm, height 12 cm and slant height 13 cm. Find volume and curved surface area.
Reveal worked answer
A sphere has radius 3 cm. Find volume and surface area.
Reveal worked answer
A prism has cross-sectional area 18 cm² and length 15 cm. Find volume.
Reveal worked answer
A closed solid hemisphere has radius 2 m. Find its total surface area.
